(2x^2+5x+5)(7x-3)=0

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Solution for (2x^2+5x+5)(7x-3)=0 equation: 


Simplifying
(2x2 + 5x + 5)(7x + -3) = 0

Reorder the terms:
(5 + 5x + 2x2)(7x + -3) = 0

Reorder the terms:
(5 + 5x + 2x2)(-3 + 7x) = 0

Multiply (5 + 5x + 2x2) * (-3 + 7x)
(5(-3 + 7x) + 5x * (-3 + 7x) + 2x2 * (-3 + 7x)) = 0
((-3 * 5 + 7x * 5) + 5x * (-3 + 7x) + 2x2 * (-3 + 7x)) = 0
((-15 + 35x) + 5x * (-3 + 7x) + 2x2 * (-3 + 7x)) = 0
(-15 + 35x + (-3 * 5x + 7x * 5x) + 2x2 * (-3 + 7x)) = 0
(-15 + 35x + (-15x + 35x2) + 2x2 * (-3 + 7x)) = 0
(-15 + 35x + -15x + 35x2 + (-3 * 2x2 + 7x * 2x2)) = 0
(-15 + 35x + -15x + 35x2 + (-6x2 + 14x3)) = 0

Combine like terms: 35x + -15x = 20x
(-15 + 20x + 35x2 + -6x2 + 14x3) = 0

Combine like terms: 35x2 + -6x2 = 29x2
(-15 + 20x + 29x2 + 14x3) = 0

Solving
-15 + 20x + 29x2 + 14x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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